36x^2+4x-364=0

Solution for 36x^2+4x-364=0 equation:

36x^2+4x-364=0

a = 36; b = 4; c = -364;
Δ = b2-4ac
Δ = 42-4·36·(-364)
Δ = 52432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{52432}=\sqrt{16*3277}=\sqrt{16}*\sqrt{3277}=4\sqrt{3277}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{3277}}{2*36}=\frac{-4-4\sqrt{3277}}{72}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{3277}}{2*36}=\frac{-4+4\sqrt{3277}}{72}
$